Question

Ethane gas is obtained in Kolbe's electrolysis of $C{H}_{3}COONa$ according to the following reaction

What volume of gas (ethane gas) at S.T.P. would be obtained by a current of 0.5 amp $(80\%$ efficient $);$ if the current is passed for $965min?$

• A. 1.8 L
• B. 2.688 L
• C. 3.45 L
• D. 11.2 L

Answer 1

Answer: (B)

n-factor = total no. of $e^{-}$ involved per molecule

$\Rightarrow$ No. of $e^{-}$ releted to 1 molecule of $C_2{H}_6=2$

$\Rightarrow$ So n factor $=2$

$gm$ eq. $\left(C_2{H}_6\right)=$ Faraday

Moles $\times n$ factor $=\frac{\text{ it }}{96500}$

$\frac{V_L}{22.4}\times 2=\frac{0.5\times \frac{80}{100}\times 965\times 60}{96500}$

$V_L=2.688L$