Ethanamide on treatment with textB textr text2 text/NaOH, gives:

Question

Ethanamide on treatment with textB textr text2 text/NaOH, gives: (A) ethanamine (B) ethyl alcohol (C) methanamine (D) bromoform

Tardigrade Admin · Accepted Answer

Amides, on reaction with textB textr text2 text/NaOH, gives one carbon less amines. This is Hofmann-bromamide reaction. CH3CONH2 xrightarrowBr2/NaOHCH3NH2

Q. Ethanamide on treatment with $B r_{2} /NaOH,$ gives:

ethanamine

ethyl alcohol

methanamine

bromoform

Amides, on reaction with $B r_{2} /NaOH,$ gives one carbon less amines. This is Hofmann-bromamide reaction. $C H_{3} CON H_{2} B r_{2} / N a O H C H_{3} N H_{2}$

Q. Ethanamide on treatment with Br2​/NaOH, gives: