Estimate the magnitude of current that passes through a wire, if 0.1 mol of electrons flow through it in 40 min. (Assume, Avagadro's number =6.0 × 1023 )

Question

Estimate the magnitude of current that passes through a wire, if 0.1 mol of electrons flow through it in 40 min. (Assume, Avagadro's number =6.0 × 1023 ) (A) 4 A (B) 9 A (C) 12 A (D) 14 A

Tardigrade Admin · Accepted Answer

Given, number of electrons, n=0.1 mol and time of flow, t=40 min =2400 s Current, I=(n Q/t)=(0.1 × 6 × 1023 × 1.6 × 10-19/2400) ⇒ I=4 A

Q. Estimate the magnitude of current that passes through a wire, if $0.1 m o l$ of electrons flow through it in $40 min .$ (Assume, Avagadro's number $= 6.0 \times 1 0^{23}$ )

4 A

9 A

12 A

14 A

Given, number of electrons, $n = 0.1 m o l$ and time of flow, $t = 40 min = 2400 s$
Current, $I = \frac{n Q}{t} = \frac{0.1 \times 6 \times 1 0 ^{23} \times 1.6 \times 1 0 ^{- 19}}{2400}$
$\Rightarrow I = 4 A$

Q. Estimate the magnitude of current that passes through a wire, if 0.1mol of electrons flow through it in 40min. (Assume, Avagadro's number =6.0×1023 )

4 A

9 A

12 A

14 A

Given, number of electrons, n=0.1mol and time of flow, t=40min=2400s Current, I=tnQ​=24000.1×6×1023×1.6×10−19​ ⇒I=4A

Q. Estimate the magnitude of current that passes through a wire, if $0.1 m o l$ of electrons flow through it in $40 min .$ (Assume, Avagadro's number $= 6.0 \times 1 0^{23}$ )

Given, number of electrons, $n = 0.1 m o l$ and time of flow, $t = 40 min = 2400 s$
Current, $I = \frac{n Q}{t} = \frac{0.1 \times 6 \times 1 0 ^{23} \times 1.6 \times 1 0 ^{- 19}}{2400}$
$\Rightarrow I = 4 A$