Escape velocity of a 1 kg body on a planet is 100 m / s. The magnitude of potential energy (in joule) of the body at that planet is

Question

Escape velocity of a 1 kg body on a planet is 100 m / s. The magnitude of potential energy (in joule) of the body at that planet is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

v text esc =√(2 G M/R) 100=√(2 G M/R) ⇒ (G M/R)=5000 Gravtiational potential energy =-(G M m/R) =-5000 × 1=-5000 J

Q. Escape velocity of a $1 k g$ body on a planet is $100 m / s$ . The magnitude of potential energy (in joule) of the body at that planet is

$v_{esc} = \frac{2 GM}{R}$
$100 = \frac{2 GM}{R}$
$\Rightarrow \frac{GM}{R} = 5000$
Gravtiational potential energy $= - \frac{GM m}{R}$
$= - 5000 \times 1 = - 5000 J$

Q. Escape velocity of a 1kg body on a planet is 100m/s. The magnitude of potential energy (in joule) of the body at that planet is

vesc ​=R2GM​​ 100=R2GM​​ ⇒RGM​=5000 Gravtiational potential energy =−RGMm​ =−5000×1=−5000J

Q. Escape velocity of a $1 k g$ body on a planet is $100 m / s$ . The magnitude of potential energy (in joule) of the body at that planet is

$v_{esc} = \frac{2 GM}{R}$
$100 = \frac{2 GM}{R}$
$\Rightarrow \frac{GM}{R} = 5000$
Gravtiational potential energy $= - \frac{GM m}{R}$
$= - 5000 \times 1 = - 5000 J$