Question

Equivalent weight of $N_2$ in the change $N_2\to N{H}_3$ is

• A. 28/6
• B. 28
• C. 28/2
• D. 28/3

Answer 1

Answer: (A)

$6e+N_2^0\to 2N^{3-}E{N}_2=\frac{28}{6}$