Equivalent weight of CuSO4 in terms of its molecular weight M in the following reaction is 2 CuSO4 + 4 KI - Cu2 I2 + I2 + 2 K2SO4

Question

Equivalent weight of CuSO4 in terms of its molecular weight M in the following reaction is 2 CuSO4 + 4 KI -> Cu2 I2 + I2 + 2 K2SO4 (A) M (B) M/2 (C) M/4 (D) M/8

Tardigrade Admin · Accepted Answer

(Equivalentweight) =( text Molecularweight / text NO.of.electronslostorgain ) The charge on Cu ion in CuSO 4 is +2 So (Equivalentweight )=( M /2). Hence option B is correct.

Q. Equivalent weight of $CuSO X_{4}$ in terms of its molecular weight M in the following reaction is $2 CuSO X_{4} + 4 KI Cu X_{2} I X_{2} + I X_{2} + 2 K X_{2} SO X_{4}$

M

M/2

M/4

M/8

(Equivalentweight) $= \frac{Molecularweight}{NO.of.electronslostorgain}$
The charge on $C u$ ion in $C u S O_{4}$ is $+ 2$
So (Equivalentweight $) = \frac{M}{2}$ .
Hence option B is correct.

Q. Equivalent weight of CuSOX4​ in terms of its molecular weight M in the following reaction is 2CuSOX4​+4KI​CuX2​ IX2​+IX2​+2KX2​SOX4​

M

M/2

M/4

M/8

(Equivalentweight) = NO.of.electronslostorgain Molecularweight ​ The charge on Cu ion in CuSO4​ is +2 So (Equivalentweight )=2M​. Hence option B is correct.

Q. Equivalent weight of $CuSO X_{4}$ in terms of its molecular weight M in the following reaction is $2 CuSO X_{4} + 4 KI Cu X_{2} I X_{2} + I X_{2} + 2 K X_{2} SO X_{4}$

(Equivalentweight) $= \frac{Molecularweight}{NO.of.electronslostorgain}$
The charge on $C u$ ion in $C u S O_{4}$ is $+ 2$
So (Equivalentweight $) = \frac{M}{2}$ .
Hence option B is correct.