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  4. Equivalent weight of CuSO4 in terms of its molecular weight M in the following reaction is 2 CuSO4 + 4 KI -> Cu2 I2 + I2 + 2 K2SO4

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Q. Equivalent weight of $\ce{CuSO_4}$ in terms of its molecular weight M in the following reaction is $\ce{2 CuSO_4 + 4 KI -> Cu_2 I_2 + I_2 + 2 K_2SO_4}$

Redox Reactions

Solution:

(Equivalentweight) $=\frac{\text { Molecularweight }}{\text { NO.of.electronslostorgain }}$
The charge on $Cu$ ion in $CuSO _{4}$ is $+2$
So (Equivalentweight $)=\frac{ M }{2}$.
Hence option B is correct.