Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
Equivalent resistance (in ohm) of the given network is
Q. Equivalent resistance (in ohm) of the given network is
3307
214
Current Electricity
Report Error
A
28
6%
B
18
82%
C
26
7%
D
25
5%
Solution:
Between points
A
and
B
all resistances are combined in series
∴
R
e
q
=
3
Ω
+
4
Ω
+
5
Ω
+
6
Ω
=
18
Ω