Question

Equivalent mass of $KMn{O}_4$ in acidic, strongly basic and neutral are in the ratio of

• A. 3 : 5 : 15
• B. 5 : 3 : 1
• C. 5 : 1 : 3
• D. 3 : 15 : 5

Answer 1

Answer: (D)

Equivalent mass of $KMn{O}_4$ in acidic, basic and neutral medium are 31.6, 158 and 52.6. The ratio will be 3 : 15 : 5.

n-factor of $KMn{O}_4$ in acidic, basic and neutral medium are 5, 1 and 3 respectively.

Acid medium : Basic medium : Neutral medium

$E_w=\frac{M_w}{5}=\frac{158}{5}$ : $E_w=\frac{M_w}{1}=\frac{158}{1}=158$ : $E_w=\frac{M_w}{3}=\frac{158}{3}$

3 : 15 : 5