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Chemistry
Equivalent mass of KMnO4 in acidic, strongly basic and neutral are in the ratio of
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Q. Equivalent mass of $KMnO_{4}$ in acidic, strongly basic and neutral are in the ratio of
NTA Abhyas
NTA Abhyas 2020
Redox Reactions
A
3 : 5 : 15
0%
B
5 : 3 : 1
0%
C
5 : 1 : 3
0%
D
3 : 15 : 5
100%
Solution:
Equivalent mass of $KMnO_{4}$ in acidic, basic and neutral medium are 31.6, 158 and 52.6. The ratio will be 3 : 15 : 5.
n-factor of $KMnO_{4}$ in acidic, basic and neutral medium are 5, 1 and 3 respectively.
Acid medium : Basic medium : Neutral medium
$E_{w}=\frac{M_{w}}{5}=\frac{158}{5}$ : $E_{w}=\frac{M_{w}}{1}=\frac{158}{1}=158$ : $E_{w}=\frac{M_{w}}{3}=\frac{158}{3}$
3 : 15 : 5