Equivalent capacitance between x and y is

Question

<img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-fhrcvqdeb8zluz0y.jpg" /> Equivalent capacitance between x and y is (A) (7/8) C (B) (8/7) C (C) (7/9) C (D) (9/7) C

Tardigrade Admin · Accepted Answer

As the circuit has a left-right symmetry, we can disconnect as shown in the figure.
Solution

C_{A B} = C + \frac{C}{2} = \frac{3 C}{2}

So, the capacitance of the equivalent circuit will be

C_{X Y} = \frac{\frac{3 C}{2} \times \frac{C}{2}}{\frac{3 C}{2} + \frac{C}{2}} + \frac{C}{2} = \frac{3 C}{8} + \frac{C}{2} \Rightarrow C_{X Y} = \frac{7 C}{8}

Q.
Equivalent capacitance between $x$ and $y$ is

$\frac{7}{8} C$

$\frac{8}{7} C$

$\frac{7}{9} C$

$\frac{9}{7} C$

Q. Equivalent capacitance between x and y is

87​C

78​C

97​C

79​C

As the circuit has a left-right symmetry, we can disconnect as shown in the figure. CAB​=C+2C​=23C​ So, the capacitance of the equivalent circuit will be CXY​=23C​+2C​23C​×2C​​+2C​=83C​+2C​⇒CXY​=87C​

Q.
Equivalent capacitance between $x$ and $y$ is

$\frac{7}{8} C$

$\frac{8}{7} C$

$\frac{7}{9} C$

$\frac{9}{7} C$