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Q.
Equivalent capacitance between $x$ and $y$ is
NTA AbhyasNTA Abhyas 2022
Solution:
As the circuit has a left-right symmetry, we can disconnect as shown in the figure.
$C_{A B}=C+\frac{C}{2}=\frac{3 C}{2}$
So, the capacitance of the equivalent circuit will be
$C_{X Y}=\frac{\frac{3 C}{2} \times \frac{C}{2}}{\frac{3 C}{2} + \frac{C}{2}}+\frac{C}{2}=\frac{3 C}{8}+\frac{C}{2}\Rightarrow C_{X Y}=\frac{7 C}{8}$
