Equilibrium constant Kp for following reaction: MgCO3 leftharpoons MgO(S) + CO2 (g)

Question

Equilibrium constant Kp for following reaction: MgCO3 leftharpoons MgO(S) + CO2 (g) (A)  Kp = PCO2 (B)  Kp = PCO2 × (PCO2 × PMgO/PMgCO3) (C)  Kp = (PCO2 + PMgO/PMgCO3) (D)  Kp = (PMgCO3/PCO2 × PMgO)

Tardigrade Admin · Accepted Answer

In heterogeneous system Kc,Kp is not based upon concentratrion or pressure of solid substance. Hence, at equilibrium their concentration or pressure are assumed as one . ∴ MgCO3(g) leftharpoons MgO(s) + CO2 (g) Kp = PCO2

Q. Equilibrium constant $K_{p}$ for following reaction :
$M g C O_{3} ⇌ M g O (S) + C O_{2} (g)$

$K p = P_{C O_{2}}$

$K p = P_{C O_{2}} \times \frac{P _{C O_{2}} \times P _{M g O}}{P _{M g C O_{3}}}$

$K p = \frac{P _{C O_{2}} + P _{M g O}}{P _{M g C O_{3}}}$

$K p = \frac{P _{M g C O_{3}}}{P _{C O_{2}} \times P _{M g O}}$

In heterogeneous system $K_{c}, K_{p}$ is not based upon concentratrion or pressure of solid substance. Hence, at equilibrium their concentration or pressure are assumed as one .
$∴ M g C O_{3} (g) ⇌ M g O (s) + C O_{2} (g)$
$K_{p} = P_{C O_{2}}$

Q. Equilibrium constant Kp​ for following reaction : MgCO3​⇌MgO(S)+CO2​(g)

Kp=PCO2​​

Kp=PCO2​​×PMgCO3​​PCO2​​×PMgO​​

Kp=PMgCO3​​PCO2​​+PMgO​​

Kp=PCO2​​×PMgO​PMgCO3​​​