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Tardigrade
Question
Mathematics
Equation of line passing through the point (1,2) and perpendicular to the line y = 3x -1 is
Q. Equation of line passing through the point
(
1
,
2
)
and perpendicular to the line
y
=
3
x
−
1
is
2621
210
KCET
KCET 2017
Straight Lines
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A
x
+
3
y
−
7
=
0
54%
B
x
+
3
y
+
7
=
0
20%
C
x
+
3
y
=
0
14%
D
x
−
3
y
=
0
11%
Solution:
Given line is
y
=
3
x
−
1
∴
Slope of the given line
=
3
∴
Slope of a line perpendicular to the given line
=
−
3
1
∴
Equation of required line will be
y
−
2
=
3
−
1
(
x
−
1
)
⇒
3
y
−
6
=
−
x
+
1
⇒
x
+
3
y
−
7
=
0