Equation of line passing through mid point of intercepts made by circle x2+y2-4 x-6 y=0 on co-ordinate axes is

Question

Equation of line passing through mid point of intercepts made by circle x2+y2-4 x-6 y=0 on co-ordinate axes is (A) 3 x+2 y-12=0 (B) 3 x+y-6=0 (C) 3 x+4 y-12=0 (D) 3 x+2 y-6=0

Tardigrade Admin · Accepted Answer

Centre (2,3) midpoint of intercept on x-axis is (2,0) and on y-axis (0,3) equation of line (x/2)+(y/3)=1

Q. Equation of line passing through mid point of intercepts made by circle $x^{2} + y^{2} - 4 x - 6 y = 0$ on co-ordinate axes is

$3 x + 2 y - 12 = 0$

$3 x + y - 6 = 0$

$3 x + 4 y - 12 = 0$

$3 x + 2 y - 6 = 0$

Centre $(2, 3)$
midpoint of intercept on $x$ -axis is $(2, 0)$ and on $y$ -axis $(0, 3)$ equation of line
$\frac{x}{2} + \frac{y}{3} = 1$

Q. Equation of line passing through mid point of intercepts made by circle x2+y2−4x−6y=0 on co-ordinate axes is

3x+2y−12=0

3x+y−6=0

3x+4y−12=0

3x+2y−6=0