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Q. Equation of line passing through mid point of intercepts made by circle $x^2+y^2-4 x-6 y=0$ on co-ordinate axes is

Conic Sections

Solution:

Centre $(2,3)$
midpoint of intercept on $x$-axis is $(2,0)$ and on $y$-axis $(0,3)$ equation of line
$\frac{x}{2}+\frac{y}{3}=1$