Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Equation of common tangent to ellipse 5 x2+2 y2=10, and hyperbola 11 x2-3 y2=33 is
Q. Equation of common tangent to ellipse
5
x
2
+
2
y
2
=
10
, and hyperbola
11
x
2
−
3
y
2
=
33
is
328
180
Conic Sections
Report Error
A
y
=
±
3
x
±
21
B
y
=
±
x
±
3
C
y
=
±
4
x
±
37
D
3
x
±
y
=
12
Solution:
c
2
=
a
2
m
2
+
b
2
=
a
2
m
−
b
2
2
m
2
+
5
=
3
m
2
−
11
⇒
m
2
=
16
=
3
x
2
−
11
⇒
y
=
±
4
x
±
37