Q.
Equation of a plane passing through three non-collinear points is
Note Where (x1,y1,z1),(x2,y2,z2) and (x3,y3,z3) are coordinates of three non-collinear points.
Let R,S and T be three non-collinear points on the plane with position vectors a,b and c, respectively.
The vector RS and RT are in the given plane. Therefore, the vector RS×RT is perpendicular to the plane containing points R,S and T. Let r be the position vector of any point P in the plane. Therefore, the equation of the plane passing through R and perpendicular to the vector RS×RT is (r−a)⋅(RS×RT)=0 (if a ⊥b, then a⋅b=0) ⇒(r−a)⋅[(b−a)×(c−a)]=0 ...(i)
This is the equation of the plane in vector form passing through three non-collinear points.
Note Why was it necessary to say that the three points had to be non-collinear? If the three points were on the same line, then there will be many planes that will contain them.
These planes will resemble the pages of a book where the line containing the points R,S and T are members in the binding of the book.
Cartesian Form
Let (x1,y1,z1),(x2,y2,z2) and (x3,y3,z3) be the coordinates of the points R,S and T, respectively. Let (x,y,z) be the coordinates of any point P on the plane with position vector
r. Then, RP=(x−x1)i^+(y−y1)j^+(z−z1)k^ RS=(x2−x1)i^+(y2−y1)j^+(z2−z1)k^ RT=(x3−x1)i^+(y3−y1)j^+(z3−z1)k^
Substituting these values in Eq. (i) of the vector form and expressing it in the form of a determinant, we have ∣∣x−x1x2−x1x3−x1y−y1y2−y1y3−y1z−z1z2−z1z3−z1∣∣=0
which is the equation of the plane in cartesian form passing through three non-collinear points (x1,y1,z1),(x2,y2,z2) and (x3,y3,z3)