Equal masses of helium and oxygen are mixed in a container at 25 °C. The fraction of the total pressure exerted by oxygen in the mixture of gases is

Question

Equal masses of helium and oxygen are mixed in a container at 25 °C. The fraction of the total pressure exerted by oxygen in the mixture of gases is (A) 1/3 (B) 2/3 (C) 1/9 (D) 4/9

Tardigrade Admin · Accepted Answer

Mole fraction of O2 =((w/32)/(w)32+(w)4 = (w/32)×(32/9 w) = (1/9) Partial pressure of oxygen =P× x/o2) =Ptotal ×(1/9) or (1/9) Ptotal

Q. Equal masses of helium and oxygen are mixed in a container at $25^{\circ} C$ . The fraction of the total pressure exerted by oxygen in the mixture of gases is

1/3

2/3

1/9

4/9

Mole fraction of $O_{2}$ = $\frac{\frac{w}{32}}{\frac{w}{32} + \frac{w}{4}}$ = $\frac{w}{32} \times \frac{32}{9 w}$ = $\frac{1}{9}$
Partial pressure of oxygen = $P \times x_{o_{2}}$
= $P_{t o t a l} \times \frac{1}{9}$ or $\frac{1}{9} P_{t o t a l}$

Q. Equal masses of helium and oxygen are mixed in a container at 25∘C. The fraction of the total pressure exerted by oxygen in the mixture of gases is

1/3

2/3

1/9

4/9

Mole fraction of O2​ =32w​+4w​32w​​ = 32w​×9w32​ = 91​ Partial pressure of oxygen =P×xo2​​ =Ptotal​×91​ or 91​Ptotal​

Q. Equal masses of helium and oxygen are mixed in a container at $25^{\circ} C$ . The fraction of the total pressure exerted by oxygen in the mixture of gases is

Mole fraction of $O_{2}$ = $\frac{\frac{w}{32}}{\frac{w}{32} + \frac{w}{4}}$ = $\frac{w}{32} \times \frac{32}{9 w}$ = $\frac{1}{9}$
Partial pressure of oxygen = $P \times x_{o_{2}}$
= $P_{t o t a l} \times \frac{1}{9}$ or $\frac{1}{9} P_{t o t a l}$