Enthalpy of vapourization of benzene is +35.3 kJ mol-1 at its boiling point of 80° C. The entropy change in the transition of the vapour to liquid at its boiling point [in JK-1 mol -1 ] is

Question

Enthalpy of vapourization of benzene is +35.3 kJ mol-1 at its boiling point of 80° C. The entropy change in the transition of the vapour to liquid at its boiling point [in JK-1 mol -1 ] is  (A) -100 (B) -441 (C) +100 (D) +441

Tardigrade Admin · Accepted Answer

Entropy change in the transition of the vapour to liquid, Δ text cond S =(Δ H text cond /Tb) =(35.3 × 103 J mol -1/(80+273) K ) =100 JK -1 mol -1

Q. Enthalpy of vapourization of benzene is $+ 35.3 k J m o l^{- 1}$ at its boiling point of $8 0^{\circ} C$ .
The entropy change in the transition of the vapour to liquid at its boiling point [in $J K^{- 1} m o l^{- 1}$ ] is ________

$- 100$

$- 441$

$+ 100$

$+ 441$

Entropy change in the transition of the vapour to liquid,

$Δ_{cond} S = \frac{Δ H _{cond}}{T _{b}}$

$= \frac{35.3 \times 1 0 ^{3} J m o l ^{- 1}}{( 80 + 273 ) K}$

$= 100 J K^{- 1} m o l^{- 1}$

Q. Enthalpy of vapourization of benzene is +35.3kJmol−1 at its boiling point of 80∘C. The entropy change in the transition of the vapour to liquid at its boiling point [in JK−1mol−1 ] is ________

−100

−441

+100

+441