Enthalpy of combustion of C (graphite) is -393.3 kJ mol-1 then for producing 39.3 kJ of heat the amount of carbon required is

Question

Enthalpy of combustion of C (graphite) is -393.3 kJ mol-1 then for producing 39.3 kJ of heat the amount of carbon required is (A) 1.5 mol (B) 0.5 mol (C) 1.2 g (D) 12 mg

Tardigrade Admin · Accepted Answer

12 g of graphite produced heat = 393.3 kJ ∴ 39.3 kJ of heat is produced from graphite = 1.2 g

Q. Enthalpy of combustion of C (graphite) is $- 393.3 k J m o l^{- 1}$ then for producing 39.3 kJ of heat the amount of carbon required is

1.5 mol

0.5 mol

1.2 g

12 mg

12 g of graphite produced heat = 393.3 kJ
$∴$ 39.3 kJ of heat is produced from
graphite = 1.2 g

Q. Enthalpy of combustion of C (graphite) is −393.3kJmol−1 then for producing 39.3 kJ of heat the amount of carbon required is