Energy stored in between the plates of parallel plate capacitor of area A, separated by distance d is

Question

Energy stored in between the plates of parallel plate capacitor of area A, separated by distance d is (A) (1/2)ε0E2 Ad (B) (1/2)ε0E2 (A/d) (C) (1/2)ε0 (d/E2A) (D) (1/2) (Ad/ε0E2)

Tardigrade Admin · Accepted Answer

Energy stored in capacitor of capacitance C with voltage V is,

U = \frac{1}{2} C V^{2}

but

C = \frac{ε _{0} A}{d}, V = E d

where A is the area of capacitor plate and d is the distance of separation and E is the electric field.

∴ U = \frac{1}{2} \frac{ε _{0} A}{d} E^{2} d^{2}

= \frac{1}{2} ε_{0} E^{2} A d

Q. Energy stored in between the plates of parallel plate capacitor of area A, separated by distance d is

$\frac{1}{2} ε_{0} E^{2} A d$

$\frac{1}{2} ε_{0} E^{2} \frac{A}{d}$

$\frac{1}{2} ε_{0} \frac{d}{E ^{2} A}$

$\frac{1}{2} \frac{A d}{ε _{0} E ^{2}}$

Q. Energy stored in between the plates of parallel plate capacitor of area A, separated by distance d is

21​ε0​E2Ad

21​ε0​E2dA​

21​ε0​E2Ad​

21​ε0​E2Ad​

Energy stored in capacitor of capacitance C with voltage V is, U=21​CV2 but C=dε0​A​,V=Ed where A is the area of capacitor plate and d is the distance of separation and E is the electric field. ∴U=21​dε0​A​E2d2 =21​ε0​E2Ad

$\frac{1}{2} ε_{0} E^{2} A d$

$\frac{1}{2} ε_{0} E^{2} \frac{A}{d}$

$\frac{1}{2} ε_{0} \frac{d}{E ^{2} A}$

$\frac{1}{2} \frac{A d}{ε _{0} E ^{2}}$