Energy required to dissociate 4 g of gaseous hydrogen in to free gaseous atoms is 208 k c a l at 25° C. The bond energy of H-H bond will be:

Question

Energy required to dissociate 4 g of gaseous hydrogen in to free gaseous atoms is 208 k c a l at 25° C. The bond energy of H-H bond will be: (A) 104 k cal (B) 104 k cal (C) 10.4 k cal (D) 1040 k cal

Tardigrade Admin · Accepted Answer

2 H2 arrow 4 H Δ H=208 k c a l H-H arrow 2 H ; Δ H=(208/2)=104 k c a l

Q. Energy required to dissociate $4 g$ of gaseous hydrogen in to free gaseous atoms is $208 k c a l$ at $2 5^{\circ} C$ . The bond energy of $H - H$ bond will be:

104 k cal

104 k cal

10.4 k cal

1040 k cal

$2 H_{2} \to 4 H$
$Δ H = 208 k c a l$
$H - H \to 2 H;$
$Δ H = \frac{208}{2} = 104 k c a l$

Q. Energy required to dissociate 4g of gaseous hydrogen in to free gaseous atoms is 208kcal at 25∘C. The bond energy of H−H bond will be:

104 k cal

104 k cal

10.4 k cal

1040 k cal

2H2​→4H ΔH=208kcal H−H→2H; ΔH=2208​=104kcal

Q. Energy required to dissociate $4 g$ of gaseous hydrogen in to free gaseous atoms is $208 k c a l$ at $2 5^{\circ} C$ . The bond energy of $H - H$ bond will be:

$2 H_{2} \to 4 H$
$Δ H = 208 k c a l$
$H - H \to 2 H;$
$Δ H = \frac{208}{2} = 104 k c a l$