Energy required for the ionisation of 0.02 gram atom of magnesium is x kJ. The amount of energy required to ionise 1 atom of magnesium is

Question

Energy required for the ionisation of 0.02 gram atom of magnesium is x kJ. The amount of energy required to ionise 1 atom of magnesium is (A) x kJ (B) (x/0.02 NA) J (C) (x × 103/0.02 N A ) J (D) x NA kJ

Tardigrade Admin · Accepted Answer

0.02 g -atom =0.02 moL atom =0.02 × N A atom 0.02 × N A atom have ionisation energy = x kJ 1 atom have ionisation energy =(x/0.02 × N A ) kJ =(x × 103/0.02 × NA) J

Q. Energy required for the ionisation of $0.02$ gram atom of magnesium is $x$ kJ. The amount of energy required to ionise $1$ atom of magnesium is

$x$ kJ

$\frac{x}{0.02 N _{A}}$ J

$\frac{x \times 1 0 ^{3}}{0.02 N _{A}}$ J

$x N_{A}$ kJ

$0.02 g$ -atom $= 0.02 m o L$ atom $= 0.02 \times N_{A}$ atom

$0.02 \times N_{A}$ atom have ionisation energy $= x k J$

1 atom have ionisation energy $= \frac{x}{0.02 \times N _{A}} k J$

$= \frac{x \times 1 0 ^{3}}{0.02 \times N _{A}} J$

Q. Energy required for the ionisation of 0.02 gram atom of magnesium is x kJ. The amount of energy required to ionise 1 atom of magnesium is

x kJ

0.02NA​x​ J

0.02NA​x×103​ J

xNA​ kJ