Question

Energy required for the ionisation of $0.02$ gram atom of magnesium is $x$ kJ. The amount of energy required to ionise $1 $ atom of magnesium is

• A. $x$ kJ
• B. $\frac{x}{0.02 N_{A}}$ J
• C. $\frac{x \times 10^{3}}{0.02 N _{ A }}$ J
• D. $x N_{A}$ kJ

Answer 1

Answer: (C)

$0.02 g$ -atom $=0.02 moL$ atom $=0.02 \times N _{ A }$ atom

$0.02 \times N _{ A }$ atom have ionisation energy $= x kJ$

1 atom have ionisation energy $=\frac{x}{0.02 \times N _{ A }} kJ$

$\,\,\,\,\,\,\,=\frac{x \times 10^{3}}{0.02 \times N_{A}} J $