Energy per unit volume for a capacitor having area A and separation d kept at potential difference V is given by

Question

Energy per unit volume for a capacitor having area A and separation d kept at potential difference V is given by (A)  (1/2) ε0 (V2/d2) (B)  (1/2 ε0) (V2/d2) (C)  (1/2) CV2 (D)  (Q2/ 2C)

Tardigrade Admin · Accepted Answer

Energy density = (1/2) ε0 (V2/d2)

Q. Energy per unit volume for a capacitor having area A and separation d kept at potential difference V is given by

$\frac{1}{2} ε_{0} \frac{V ^{2}}{d ^{2}}$

$\frac{1}{2 ε _{0}} \frac{V ^{2}}{d ^{2}}$

$\frac{1}{2} C V^{2}$

$\frac{Q ^{2}}{2 C}$

Energy density = $\frac{1}{2} ε_{0} \frac{V ^{2}}{d ^{2}}$

Q. Energy per unit volume for a capacitor having area A and separation d kept at potential difference V is given by

21​ε0​d2V2​

2ε0​1​d2V2​

21​CV2

2CQ2​

Energy density = 21​ε0​d2V2​

$\frac{1}{2} ε_{0} \frac{V ^{2}}{d ^{2}}$

$\frac{1}{2 ε _{0}} \frac{V ^{2}}{d ^{2}}$

$\frac{1}{2} C V^{2}$

$\frac{Q ^{2}}{2 C}$

Energy density = $\frac{1}{2} ε_{0} \frac{V ^{2}}{d ^{2}}$