Energy of a photon is given by E= hv where v is the number of vibrations per second and h is Planck's constant. Dimensions of Planck's constant are

Question

Energy of a photon is given by E= hv where v is the number of vibrations per second and h is Planck's constant. Dimensions of Planck's constant are (A) [ M 0 L 0 T 0] (B) [ ML 2 T -1] (C) [ ML 2 T -2] (D) [ ML 2 T -3]

Tardigrade Admin · Accepted Answer

E=h v or h=(E/v) So, dimensions of h=( text dimensions of E/ text Dimensions of v) =([M L2 T-2]/[M0 L0 T-1])=[M L2 T-1] =([M L2 T-2]/[M0 L0 T-1])=[M L2 T-1]

Q. Energy of a photon is given by $E = h v$ where $v$ is the number of vibrations per second and $h$ is Planck's constant. Dimensions of Planck's constant are

$[M^{0} L^{0} T^{0}]$

$[M L^{2} T^{- 1}]$

$[M L^{2} T^{- 2}]$

$[M L^{2} T^{- 3}]$

$E = h v$ or $h = \frac{E}{v}$
So, dimensions of $h = \frac{dimensions of E}{Dimensions of v}$
$= \frac{[ M L ^{2} T ^{- 2} ]}{[ M ^{0} L ^{0} T ^{- 1} ]} = [M L^{2} T^{- 1}]$
$= \frac{[ M L ^{2} T ^{- 2} ]}{[ M ^{0} L ^{0} T ^{- 1} ]} = [M L^{2} T^{- 1}]$

Q. Energy of a photon is given by E=hv where v is the number of vibrations per second and h is Planck's constant. Dimensions of Planck's constant are

[M0L0T0]

[ML2T−1]

[ML2T−2]

[ML2T−3]