Energy emitted by a black body and wavelength relations at temperature T1 K , T2 K, and T3 K, are shown by curves. The relation between the temperatures is

Question

Energy emitted by a black body and wavelength relations at temperature T1 K , T2 K, and T3 K, are shown by curves. The relation between the temperatures is (A) T 3>T2>T1 (B) T 1>T2>T3 (C) T 1=T2=T3 (D) T 1, T2, T3 bear no relation

Tardigrade Admin · Accepted Answer

From Wien's displacement law λm T= constant. This equation shows that as temperature of black body rises, the maximum energy of emitted radiation shifts towards shorter wavelength, hence higher energy (E=(h c/λ)). Where λ is wavelength.

Q. Energy emitted by a black body and wavelength relations at temperature $T_{1} K, T_{2} K$ , and $T_{3} K$ , are shown by curves. The relation between the temperatures is

$T_{3} > T_{2} > T_{1}$

$T_{1} > T_{2} > T_{3}$

$T_{1} = T_{2} = T_{3}$

$T_{1}, T_{2}, T_{3}$ bear no relation

From Wien's displacement law
$λ_{m} T =$ constant.
This equation shows that as temperature of black body rises, the maximum energy of emitted radiation shifts towards shorter wavelength, hence higher energy $(E = \frac{h c}{λ})$ .
Where $λ$ is wavelength.

Q. Energy emitted by a black body and wavelength relations at temperature T1​K,T2​K, and T3​K, are shown by curves. The relation between the temperatures is

T3​>T2​>T1​

T1​>T2​>T3​

T1​=T2​=T3​

T1​,T2​,T3​ bear no relation