Question

Energy emitted by a black body and wavelength relations at temperature $T_{1} K , T_{2} K$, and $T_{3} K$, are shown by curves. The relation between the temperatures is

• A. $T _{3}>T_{2}>T_{1}$
• B. $T _{1}>T_{2}>T_{3}$
• C. $T _{1}=T_{2}=T_{3}$
• D. $T _{1}, T_{2}, T_{3}$ bear no relation

Answer 1

Answer: (A)

From Wien's displacement law
$\lambda_{m} T=$ constant.
This equation shows that as temperature of black body rises, the maximum energy of emitted radiation shifts towards shorter wavelength, hence higher energy $\left(E=\frac{h c}{\lambda}\right)$.
Where $\lambda$ is wavelength.