Empirical formula of compound having molar mass 58 is C2H5 . Number of structural isomers possible, are

Question

Empirical formula of compound having molar mass 58 is C2H5 . Number of structural isomers possible, are (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

Empirical formula is C2 H5. Empirical mass formula =29. Molar mass =58 Molecular formula will be C4 H10. The molecular formula is C4 H10 and the isomers are two (chair isomers) in number. CH 3- CH 2- CH 2- CH 3, CH 3- underset overset|CH3CH - CH 3

Q. Empirical formula of compound having molar mass $58$ is $C_{2} H_{5}$ . Number of structural isomers possible, are

1

2

3

4

Empirical formula is $C_{2} H_{5}$ .
Empirical mass formula $= 29$ .
Molar mass $= 58$ Molecular formula will be $C_{4} H_{10}$ .
The molecular formula is $C_{4} H_{10}$ and the isomers are two (chair isomers) in number.
$C H_{3} - C H_{2} - C H_{2} - C H_{3}, C H_{3} - C H_{3} ∣ C H - C H_{3}$

Q. Empirical formula of compound having molar mass 58 is C2​H5​ . Number of structural isomers possible, are

1

2

3

4

Empirical formula is C2​H5​. Empirical mass formula =29. Molar mass =58 Molecular formula will be C4​H10​. The molecular formula is C4​H10​ and the isomers are two (chair isomers) in number. CH3​−CH2​−CH2​−CH3​,CH3​−CH3​∣​C​H−CH3​

Q. Empirical formula of compound having molar mass $58$ is $C_{2} H_{5}$ . Number of structural isomers possible, are

Empirical formula is $C_{2} H_{5}$ .
Empirical mass formula $= 29$ .
Molar mass $= 58$ Molecular formula will be $C_{4} H_{10}$ .
The molecular formula is $C_{4} H_{10}$ and the isomers are two (chair isomers) in number.
$C H_{3} - C H_{2} - C H_{2} - C H_{3}, C H_{3} - C H_{3} ∣ C H - C H_{3}$