Empirical formula of a compound is CH2O and its molecular mass is 90, the molecular formula of the compound is

Question

Empirical formula of a compound is CH2O and its molecular mass is 90, the molecular formula of the compound is (A) C3H6O3 (B) C2H4O2 (C) C6H12O6 (D) CH2O

Tardigrade Admin · Accepted Answer

The empirical formula of compound = CH 2 O Empirical formula mass =(1 × 12)+(2 × 1)+(1 × 16)=30 Molecular mass =90 ∴ n=( text Molecular mass / text Empirical mass )=(90/30)=3 and molecular formula =3 × CH 2 O = C 3 H 6 O 3

Q. Empirical formula of a compound is $C H_{2} O$ and its molecular mass is $90$ , the molecular formula of the compound is

$C_{3} H_{6} O_{3}$

$C_{2} H_{4} O_{2}$

$C_{6} H_{12} O_{6}$

$C H_{2} O$

The empirical formula of compound $= C H_{2} O$

Empirical formula mass

$= (1 \times 12) + (2 \times 1) + (1 \times 16) = 30$

Molecular mass $= 90$

$∴ n = \frac{Molecular mass}{Empirical mass} = \frac{90}{30} = 3$

and molecular formula $= 3 \times C H_{2} O$

$= C_{3} H_{6} O_{3}$

Q. Empirical formula of a compound is CH2​O and its molecular mass is 90, the molecular formula of the compound is

C3​H6​O3​

C2​H4​O2​

C6​H12​O6​

CH2​O