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Q. Empirical formula of a compound is $CH_2O$ and its molecular mass is $90$, the molecular formula of the compound is

KCETKCET 2013Organic Chemistry – Some Basic Principles and Techniques

Solution:

The empirical formula of compound $= CH _{2} O$

Empirical formula mass

$=(1 \times 12)+(2 \times 1)+(1 \times 16)=30$

Molecular mass $=90$

$\therefore n=\frac{\text { Molecular mass }}{\text { Empirical mass }}=\frac{90}{30}=3$

and molecular formula $=3 \times CH _{2} O$

$= C _{3} H _{6} O _{3}$