EMF of the given cell A ( s )| A ( aq )2+ | B ( aq )2+| B ( s ) Given E A / A 2+°:+1.4 V and E B / B 2+°:-1.4 V

Question

EMF of the given cell A ( s )| A ( aq )2+ | B ( aq )2+| B ( s ) Given E A / A 2+°:+1.4 V and E B / B 2+°:-1.4 V (A) 2.8 V (B) 1.8 V (C) 0 V (D) -1.8 V

Tardigrade Admin · Accepted Answer

E text cell 0 =( E text cathode 0) SRP -( E text anode 0) SRP =( E text anode 0) SOP -( E text cathode 0) SOP Where SRP is standard reduction potential and SOP is standard oxidation potential ∴ E Cell =[1.4-(-1.4)] V =+2.8 V

Q. EMF of the given cell
$A_{(s)} ∣ ∣ A_{(a q)}^{2 +} ∥ B_{(a q)}^{2 +} ∣ ∣ B_{(s)}$
Given $E_{A / A^{2 +}}^{\circ} : + 1.4 V$ and $E_{B / B^{2 +}}^{\circ} : - 1.4 V$

$2.8 V$

$1.8 V$

$0 V$

$- 1.8 V$

$E_{cell}^{0} = (E_{cathode}^{0})_{SRP} - (E_{anode}^{0})_{SRP}$
$= (E_{anode}^{0})_{SOP} - (E_{cathode}^{0})_{SOP}$
Where SRP is standard reduction potential and SOP is standard oxidation potential
$∴ E_{C e ll} = [1.4 - (- 1.4)] V$
$= + 2.8 V$

Q. EMF of the given cell A(s)​∣∣​A(aq)2+​∥B(aq)2+​∣∣​B(s)​ Given EA/A2+∘​:+1.4V and EB/B2+∘​:−1.4V

2.8V

1.8V

0V

−1.8V