Elevation in boiling point for 1.5 molal solution of glucose in water is 4 K. The depression in freezing point for 4.5 molal solution of glucose in water is 4 K. The ratio of molal elevation constant to molal depression constant ( K b / K f ) is

Question

Elevation in boiling point for 1.5 molal solution of glucose in water is 4 K. The depression in freezing point for 4.5 molal solution of glucose in water is 4 K. The ratio of molal elevation constant to molal depression constant ( K b / K f ) is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ T b = iK b m Δ T f = iK f m (4/4)=( K b 1.5/ K f 4.5) ( K b / K f )=3

Q. Elevation in boiling point for $1.5$ molal solution of glucose in water is $4 K$ . The depression in freezing point for $4.5$ molal solution of glucose in water is $4 K$ . The ratio of molal elevation constant to molal depression constant $(K_{b} / K_{f})$ is ___

$Δ T_{b} = i K_{b} m$
$Δ T_{f} = i K_{f} m$
$\frac{4}{4} = \frac{K _{b} 1.5}{K _{f} 4.5}$
$\frac{K _{b}}{K _{f}} = 3$

Q. Elevation in boiling point for 1.5 molal solution of glucose in water is 4K. The depression in freezing point for 4.5 molal solution of glucose in water is 4K. The ratio of molal elevation constant to molal depression constant (Kb​/Kf​) is ___

ΔTb​=iKb​m ΔTf​=iKf​m 44​=Kf​4.5Kb​1.5​ Kf​Kb​​=3

Q. Elevation in boiling point for $1.5$ molal solution of glucose in water is $4 K$ . The depression in freezing point for $4.5$ molal solution of glucose in water is $4 K$ . The ratio of molal elevation constant to molal depression constant $(K_{b} / K_{f})$ is ___

$Δ T_{b} = i K_{b} m$
$Δ T_{f} = i K_{f} m$
$\frac{4}{4} = \frac{K _{b} 1.5}{K _{f} 4.5}$
$\frac{K _{b}}{K _{f}} = 3$