Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is :

Question

Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is : (A) A 2 BO 4 (B) A 2 B 2 O (C) A 4 B 2 O (D) AB 2 O 4

Tardigrade Admin · Accepted Answer

ZB = 4, ZA = 4 ×(1/2) = 2, ZO =8 Formula ; A2B2O8 ≡ AB2O4

Q. Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is :

$A_{2} B O_{4}$

$A_{2} B_{2} O$

$A_{4} B_{2} O$

$A B_{2} O_{4}$

$Z_{B} = 4, Z_{A} = 4 \times \frac{1}{2} = 2, Z_{O} = 8$
Formula ; $A_{2} B_{2} O_{8} \equiv A B_{2} O_{4}$

Q. Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is :

A2​BO4​

A2​B2​O

A4​B2​O

AB2​O4​

ZB​=4,ZA​=4×21​=2,ZO​=8 Formula ; A2​B2​O8​≡AB2​O4​

$A_{2} B O_{4}$

$A_{2} B_{2} O$

$A_{4} B_{2} O$

$A B_{2} O_{4}$

$Z_{B} = 4, Z_{A} = 4 \times \frac{1}{2} = 2, Z_{O} = 8$
Formula ; $A_{2} B_{2} O_{8} \equiv A B_{2} O_{4}$