Question

Electronic configuration (outermost) of $M{n}^{2+}$ ion(At. No. of Mn = 25) in its ground state is

• A. $3d^{5}4s^0$
• B. $3d^4{s}^1$
• C. $3d^{3}4s^2$
• D. $3d^{2}4s^2{p}^2$

Answer 1

Answer: (A)

Mn(Z = 25) : $[Ar{]}^{18}4s^{2}3d^5$
$M{n}^{2+}:[Ar{]}^{18}3d^{5}4s^0$