Question

Electronegativity value on Mullikan scale for two different elements are given as $7$ and $1.4$, respectively. If bond is formed between them, then calculate the percentage ionic character of the bond between them.
$[E{N}_P=E{N}_M/2.8$, use Hanny Smith formula, \% ionic character $=16\Delta +3.5{\Delta }^2]$

Answer 1

Answer: 46

E.N. on Pauling scale $=\frac{7}{2.8}=2.5$
E.N. on Pauling scale for $2$ nd element $=\frac{1.4}{2.8}=0.5$
Electronegativity difference $\Delta =2.5-0.5=2$
$\therefore \%$ ionic character $=16\Delta +3.5{\Delta }^2$
$=16\times 2+3.5\times 2^2$
$=32+14=46\%$