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Q. Electronegativity value on Mullikan scale for two different elements are given as $7$ and $1.4$, respectively. If bond is formed between them, then calculate the percentage ionic character of the bond between them.
$\left[ EN _{ P }= EN _{ M } / 2.8\right.$, use Hanny Smith formula, \% ionic character $\left.=16 \Delta+3.5 \Delta^{2}\right]$

Classification of Elements and Periodicity in Properties

Solution:

E.N. on Pauling scale $=\frac{7}{2.8}=2.5$
E.N. on Pauling scale for $2 $ nd element $=\frac{1.4}{2.8}=0.5$
Electronegativity difference $\Delta=2.5-0.5=2$
$\therefore \%$ ionic character $=16 \Delta+3.5 \Delta^{2}$
$=16 \times 2+3.5 \times 2^{2}$
$=32+14=46 \%$