Electron Affinity of Cl is 3.7 eV. How much Energy released in kCal when 2g of gaseous chlorine atoms is converted to Cl- ions in the gaseous state.

Question

Electron Affinity of Cl is 3.7 eV. How much Energy released in kCal when 2g of gaseous chlorine atoms is converted to Cl- ions in the gaseous state. (A)  text4.80 kCal (B)  text5.20 kCal (C)  text1.50 kCal (D)  text3.60 kCal

Tardigrade Admin · Accepted Answer

Moles of Cl(g)= (2/35 . 5) = 0.0563mole Energy Released, 1ev/atom=96.5kJ/mole = 0.0563× 3.7× 96.5 = 20.10kJ = (20 .10/4 . 184) = 4.80kCal

Q. Electron Affinity of Cl is 3.7 eV. How much Energy released in kCal when 2g of gaseous chlorine atoms is converted to Cl^- ions in the gaseous state.

$4.80 kCal$

$5.20 kCal$

$1.50 kCal$

$3.60 kCal$

Moles of Cl(g)= $\frac{2}{35.5}$ = $0.0563 m o l e$
Energy Released,
$1 e v / a t o m = 96.5 k J / m o l e$
= $0.0563 \times 3.7 \times 96.5 = 20.10 k J$
= $\frac{20.10}{4.184}$ = $4.80 k C a l$

Q. Electron Affinity of Cl is 3.7 eV. How much Energy released in kCal when 2g of gaseous chlorine atoms is converted to Cl- ions in the gaseous state.

4.80 kCal

5.20 kCal

1.50 kCal

3.60 kCal