Question

Electrode potential for $Ag$ electrode varies according to the equation
$E_{A{g}^{+}/Ag}=E_{A{g}^{+}/Ag}^{\circ }-\frac{0.059}{1}\log \frac{1}{\left[A{g}^{+}\right]}$
If the graph of $E_{A{g}^{+}/Ag}$ versus $\log \left[A{g}^{+}\right]$is plotted, the value of slope is_______

Answer 1

Answer: 0.059

$E_{A{g}^{+}/Ag}=E_{A{g}^{+}/Ag}^{\circ }-\frac{0.059}{1}\log \frac{1}{\left[A{g}^{+}\right]}$
$\therefore E_{A{g}^{+}/Ag}=E_{A{g}^{+}/Ag}^0+\frac{0.059}{1}\log \left[A{g}^{+}\right]$
This is the general form of $y=mx+c$.
$\therefore$ Slope $=m=0.059$