Electrode potential data given below Cl2+2H2O arrow 2ClO-+4H++2e-;E° =-1.61volt ClO-+2H2O arrow ClO3 -+4H++4e-;E° =-0.50volt Based on these data which is the spontaneous reaction.

Question

Electrode potential data given below Cl2+2H2O arrow 2ClO-+4H++2e-;E° =-1.61volt ClO-+2H2O arrow ClO3 -+4H++4e-;E° =-0.50volt Based on these data which is the spontaneous reaction. (A) Cl2+ClO-+ClO3 - (B) ClO- arrow Cl2+ClO3 - (C) ClO3 - arrow Cl2+ClO- (D) ClO-+Cl2 arrow ClO3 -

Tardigrade Admin · Accepted Answer

Given electron potential data is- Cl2+2H2O arrow 2ClO-+4H++2e-;E° =-1.61 Volt ClO-+2H2O arrow ClO3-+4H++4e-;E° =-0.50 Volt For reaction to be spontaneous E0 reaction should +ve , Thus substracting equation 1 from equation 2.

Q. Electrode potential data given below

$C l_{2} + 2 H_{2} O \to 2 Cl O^{-} + 4 H^{+} + 2 e^{-}; E^{\circ} = - 1.61 v o lt$

$Cl O^{-} + 2 H_{2} O \to Cl O_{3}^{-} + 4 H^{+} + 4 e^{-}; E^{\circ} = - 0.50 v o lt$

Based on these data which is the spontaneous reaction.

$C l_{2} + Cl O^{-} + Cl O_{3}^{-}$

$Cl O^{-} \to C l_{2} + Cl O_{3}^{-}$

$Cl O_{3}^{-} \to C l_{2} + Cl O^{-}$

$Cl O^{-} + C l_{2} \to Cl O_{3}^{-}$

Q. Electrode potential data given below Cl2​+2H2​O→2ClO−+4H++2e−;E∘=−1.61volt ClO−+2H2​O→ClO3−​+4H++4e−;E∘=−0.50volt Based on these data which is the spontaneous reaction.

Cl2​+ClO−+ClO3−​

ClO−→Cl2​+ClO3−​

ClO3−​→Cl2​+ClO−

ClO−+Cl2​→ClO3−​

Given electron potential data is- Cl2​+2H2​O→2ClO−+4H++2e−;E∘=−1.61 Volt ClO−+2H2​O→ClO3−​+4H++4e−;E∘=−0.50 Volt For reaction to be spontaneous E0 reaction should +ve , Thus substracting equation 1 from equation 2.

Q. Electrode potential data given below

$C l_{2} + 2 H_{2} O \to 2 Cl O^{-} + 4 H^{+} + 2 e^{-}; E^{\circ} = - 1.61 v o lt$

$Cl O^{-} + 2 H_{2} O \to Cl O_{3}^{-} + 4 H^{+} + 4 e^{-}; E^{\circ} = - 0.50 v o lt$

Based on these data which is the spontaneous reaction.

$C l_{2} + Cl O^{-} + Cl O_{3}^{-}$

$Cl O^{-} \to C l_{2} + Cl O_{3}^{-}$

$Cl O_{3}^{-} \to C l_{2} + Cl O^{-}$

$Cl O^{-} + C l_{2} \to Cl O_{3}^{-}$