Electric field (E) and current density (J) have relation

Question

Electric field (E) and current density (J) have relation (A)  Eα J-1  (B)  Eα J  (C)  Eα (1/J2)  (D)  E2α (1/J)

Tardigrade Admin · Accepted Answer

Current density relates with electric field as mathbfJ=σ mathbfE=( mathbfE/ρ ); where σ = conductivity and ρ = resistivity or specific resistance of substance.

Q. Electric field (E) and current density (J) have relation

$E α J^{- 1}$

$E α J$

$E α \frac{1}{J ^{2}}$

$E^{2} α \frac{1}{J}$

Current density relates with electric field as $J = σ E = \frac{E}{ρ};$ where $σ$ = conductivity and $ρ$ = resistivity or specific resistance of substance.

Q. Electric field (E) and current density (J) have relation

EαJ−1

EαJ

EαJ21​

E2αJ1​

Current density relates with electric field as J=σE=ρE​; where σ = conductivity and ρ = resistivity or specific resistance of substance.

$E α J^{- 1}$

$E α J$

$E α \frac{1}{J ^{2}}$

$E^{2} α \frac{1}{J}$

Current density relates with electric field as $J = σ E = \frac{E}{ρ};$ where $σ$ = conductivity and $ρ$ = resistivity or specific resistance of substance.