Question

Electric field (E) and current density (J) have relation

• A. $ E\alpha {{J}^{-1}} $
• B. $ E\alpha J $
• C. $ E\alpha \frac{1}{{{J}^{2}}} $
• D. $ {{E}^{2}}\alpha \frac{1}{J} $

Answer 1

Answer: (B)

Current density relates with electric field as $ \overrightarrow{\mathbf{J}}=\sigma \overrightarrow{\mathbf{E}}=\frac{\overrightarrow{\mathbf{E}}}{\rho }; $ where $ \sigma $ = conductivity and $ \rho $ = resistivity or specific resistance of substance.