Electric charges + 10μ C, + 5μ C, - 3 μ C and + 8 μ C are placed at the corners of a square of side √2 m. The potential at the centre of the square (V) is

Question

Electric charges + 10μ C, + 5μ C, - 3 μ C and + 8 μ C are placed at the corners of a square of side √2 m. The potential at the centre of the square (V) is (A) 18× 105 (B) 1.8× 106 (C) 1.8 (D) 1.8× 105

Tardigrade Admin · Accepted Answer

V = 9 × 109 ( (10 × 10-6/1) + (5 × 10-6/1) - (3 × 10-6/1) + (8 × 10-6/1) ) = 1.8 × 105 V

Q. Electric charges $+ 10 μ C, + 5 μ C, - 3 μ C an d + 8 μ C$ are placed at the corners of a square of side $2 m$ . The potential at the centre of the square (V) is

$18 \times 1 0^{5}$

$1.8 \times 1 0^{6}$

1.8

$1.8 \times 1 0^{5}$

V = $9 \times 1 0^{9} (\frac{10 \times 1 0 ^{- 6}}{1} + \frac{5 \times 1 0 ^{- 6}}{1} - \frac{3 \times 1 0 ^{- 6}}{1} + \frac{8 \times 1 0 ^{- 6}}{1})$
= 1.8 $\times 1 0^{5}$ V

Q. Electric charges +10μC,+5μC,−3μCand+8μC are placed at the corners of a square of side 2​m. The potential at the centre of the square (V) is

18×105

1.8×106

1.8

1.8×105

V = 9×109(110×10−6​+15×10−6​−13×10−6​+18×10−6​) = 1.8 ×105 V

Q. Electric charges $+ 10 μ C, + 5 μ C, - 3 μ C an d + 8 μ C$ are placed at the corners of a square of side $2 m$ . The potential at the centre of the square (V) is

$18 \times 1 0^{5}$

$1.8 \times 1 0^{6}$

$1.8 \times 1 0^{5}$

V = $9 \times 1 0^{9} (\frac{10 \times 1 0 ^{- 6}}{1} + \frac{5 \times 1 0 ^{- 6}}{1} - \frac{3 \times 1 0 ^{- 6}}{1} + \frac{8 \times 1 0 ^{- 6}}{1})$
= 1.8 $\times 1 0^{5}$ V