Eight drops of mercury of equal radii combine to form a big drop. The capacitance of a bigger drop as compared to each smaller drop is

Question

Eight drops of mercury of equal radii combine to form a big drop. The capacitance of a bigger drop as compared to each smaller drop is (A) 2 times (B) 8 times (C) 4 times (D) 16 times

Tardigrade Admin · Accepted Answer

CB=n(1/3) CS CB=8(1/3) CS CB=2 CS

Q. Eight drops of mercury of equal radii combine to form a big drop. The capacitance of a bigger drop as compared to each smaller drop is

2 times

8 times

4 times

16 times

$C_{B} = n^{\frac{1}{3}} C_{S}$
$C_{B} = 8^{\frac{1}{3}} C_{S}$
$C_{B} = 2 C_{S}$

Q. Eight drops of mercury of equal radii combine to form a big drop. The capacitance of a bigger drop as compared to each smaller drop is

2 times

8 times

4 times

16 times

CB​=n31​CS​ CB​=831​CS​ CB​=2CS​

$C_{B} = n^{\frac{1}{3}} C_{S}$
$C_{B} = 8^{\frac{1}{3}} C_{S}$
$C_{B} = 2 C_{S}$