Eight dipoles of charges of magnitude q are placed inside a cube. The total electric flux through the cube will be

Question

Eight dipoles of charges of magnitude q are placed inside a cube. The total electric flux through the cube will be (A) (8 q/ε0) (B) (16 q/ε0) (C) (q/ε0) (D) zero

Tardigrade Admin · Accepted Answer

since a dipole consists of two equal and opposite charges, the net charge of a dipole is zero.

Q. Eight dipoles of charges of magnitude $q$ are placed inside a cube. The total electric flux through the cube will be

$\frac{8 q}{ε _{0}}$

$\frac{16 q}{ε _{0}}$

$\frac{q}{ε _{0}}$

zero

since a dipole consists of two equal and opposite charges, the net charge of a dipole is zero.

Q. Eight dipoles of charges of magnitude q are placed inside a cube. The total electric flux through the cube will be

ε0​8q​

ε0​16q​

ε0​q​

zero

since a dipole consists of two equal and opposite charges, the net charge of a dipole is zero.

Q. Eight dipoles of charges of magnitude $q$ are placed inside a cube. The total electric flux through the cube will be

$\frac{8 q}{ε _{0}}$

$\frac{16 q}{ε _{0}}$

$\frac{q}{ε _{0}}$