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Question
Chemistry
Efficiency of the following cells is 84%. A(.s.)+B2 +(.aq.)leftharpoons A2 +(.aq.)+B(.s.) ; Δ H=-285 kJ Then the standard electrode potential of the cell will be
Q. Efficiency of the following cells is 84%.
A
(
s
)
+
B
2
+
(
a
q
)
⇌
A
2
+
(
a
q
)
+
B
(
s
)
;
Δ
H
=
−
285
kJ
Then the standard electrode potential of the cell will be
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NTA Abhyas
NTA Abhyas 2020
Electrochemistry
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A
1.20 V
B
2.40 V
C
1.10 V
D
1.24 V
Solution:
Efficiency
=
Δ
H
∘
Δ
G
∘
=
Δ
H
∘
−
n
F
E
∘
0.84
=
−
285
×
1000
−
2
×
E
∘
×
96500
E
∘
=
+
1.24
V
.