EDTA4- forms very stable complexes with most of the transition metals. In an octahedral [ M ( EDTA )]2- complex where M is in +2 oxidation state, the number of M - O bonds is/are.

Question

EDTA4- forms very stable complexes with most of the transition metals. In an octahedral [ M ( EDTA )]2- complex where M is in +2 oxidation state, the number of M - O bonds is/are. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The donor atoms in EDTA 4- are 2 N-atoms and 4 negatively charged O-atoms. When EDTA 4- ion bonds to a metal ion ( M n +), it forms six bonds (i.e., 2 M - N bonds and 4 M - O bonds).

Q. $E D T A^{4 -}$ forms very stable complexes with most of the transition metals. In an octahedral $[M (E D T A)]^{2 -}$ complex where $M$ is in $+ 2$ oxidation state, the number of $M - O$ bonds is/are____.

The donor atoms in $E D T A^{4 -}$ are $2 N$ -atoms and $4$ negatively charged $O$ -atoms. When $E D T A^{4 -}$ ion bonds to a metal ion $(M^{n^{+}})$ , it forms six bonds (i.e., $2 M - N$ bonds and $4 M - O$ bonds).

Q. EDTA4− forms very stable complexes with most of the transition metals. In an octahedral [M(EDTA)]2− complex where M is in +2 oxidation state, the number of M−O bonds is/are____.

The donor atoms in EDTA4− are 2N-atoms and 4 negatively charged O-atoms. When EDTA4− ion bonds to a metal ion (Mn+), it forms six bonds (i.e., 2M−N bonds and 4M−O bonds).

Q. $E D T A^{4 -}$ forms very stable complexes with most of the transition metals. In an octahedral $[M (E D T A)]^{2 -}$ complex where $M$ is in $+ 2$ oxidation state, the number of $M - O$ bonds is/are____.

The donor atoms in $E D T A^{4 -}$ are $2 N$ -atoms and $4$ negatively charged $O$ -atoms. When $E D T A^{4 -}$ ion bonds to a metal ion $(M^{n^{+}})$ , it forms six bonds (i.e., $2 M - N$ bonds and $4 M - O$ bonds).