E° cell of a galvanic cell is 1.1 V. Standard free energy change can be given as

Question

E° cell of a galvanic cell is 1.1 V. Standard free energy change can be given as (A) -212.27 kJ mol -1 (B) -212.27 J mol -1 (C) +212.27 kJ mol -1 (D) +212.27 V

Tardigrade Admin · Accepted Answer

For a glavanic cell Z n+C u2+ arrow C u+Z n2+ Δ G°=-n F E° n=2, E°=1.1 V F=96500 C mol -1 Δ G°=-2 × 96500 × 1.1 =-212300 J mol -1 =-212.3 J mol -1

Q. $E^{\circ}$ cell of a galvanic cell is $1.1 V$ . Standard free energy change can be given as

$- 212.27 k J m o l^{- 1}$

$- 212.27 J m o l^{- 1}$

$+ 212.27 k J m o l^{- 1}$

$+ 212.27 V$

For a glavanic cell $Z n + C u^{2 +} \to C u + Z n^{2 +}$
$Δ G^{\circ} = - n F E^{\circ}$
$n = 2, E^{\circ} = 1.1 V$
$F = 96500 C m o l^{- 1}$
$Δ G^{\circ} = - 2 \times 96500 \times 1.1$
$= - 212300 J m o l^{- 1}$
$= - 212.3 J m o l^{- 1}$

Q. E∘ cell of a galvanic cell is 1.1V. Standard free energy change can be given as

−212.27kJmol−1

−212.27Jmol−1

+212.27kJmol−1

+212.27V