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Chemistry
E° cell of a galvanic cell is 1.1 V. Standard free energy change can be given as
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Q. $E^{\circ}$ cell of a galvanic cell is $1.1\, V$. Standard free energy change can be given as
AMU
AMU 2011
Electrochemistry
A
$-212.27 \,kJ\, mol ^{-1}$
63%
B
$-212.27 \,J\, mol ^{-1}$
13%
C
$+212.27 \,kJ\, mol ^{-1}$
22%
D
$+212.27 \,V$
2%
Solution:
For a glavanic cell $Z n+C u^{2+} \rightarrow C u+Z n^{2+}$
$\Delta G^{\circ}=-n F \,E^{\circ}$
$n=2, E^{\circ}=1.1 \,V$
$F=96500 \,C\,mol ^{-1}$
$\Delta G^{\circ}=-2 \times 96500 \times 1.1$
$=-212300\, J\,mol ^{-1}$
$=-212.3 \,J\,mol ^{-1}$